8x^2+1=201

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Solution for 8x^2+1=201 equation:



8x^2+1=201
We move all terms to the left:
8x^2+1-(201)=0
We add all the numbers together, and all the variables
8x^2-200=0
a = 8; b = 0; c = -200;
Δ = b2-4ac
Δ = 02-4·8·(-200)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*8}=\frac{-80}{16} =-5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*8}=\frac{80}{16} =5 $

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